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判断时间的正则表达式

2017年12月12日  | 移动技术网IT编程  | 我要评论
普通方法为,分离出小时、分钟、秒分别进行判断:
public static boolean timecheck(string time, string owner) {
//检查时间字符串time是否满足格式“hh:mm:ss”或“hh:mm”,若不满足显示相应消息,并返回false
if(time.equals("")){
string msg = owner+" : "+"time is empty.";
messagedialog.showerror(controller.getmainframe(), msg);
return false;
}
int hours, minutes, seconds = 0;
stringtokenizer st = new stringtokenizer(time, ":");
int tokens = st.counttokens();
if (tokens != 3 && tokens != 2) {
string msg = owner+" : "+"time " + time + " does not conform to the hh:mm:ss format, nor hh:mm format.";
messagedialog.showerror(controller.getmainframe(), msg);
return false;
}
string hourtoken = st.nexttoken();
try {
hours = integer.parseint(hourtoken);
} catch (numberformatexception nfe) {
string msg = owner+" : "+hourtoken + " in " + time + " can not be parsed as hours.";
messagedialog.showerror(controller.getmainframe(), msg);
return false;
}
string minutetoken = st.nexttoken();
try {
minutes = integer.parseint(minutetoken);
} catch (numberformatexception nfe) {
string msg = owner+" : "+minutetoken + " in " + time + " can not be parsed as minutes.";
messagedialog.showerror(controller.getmainframe(), msg);
return false;
}
if(tokens == 3){
string secondtoken = st.nexttoken();
try {
seconds = integer.parseint(secondtoken);
} catch (numberformatexception nfe) {
string msg = owner+" : "+secondtoken + " in " + time + " can not be parsed as seconds.";
messagedialog.showerror(controller.getmainframe(), msg);
return false;
}
}
if (hours < 0 || hours > 23) {
string msg = owner+" : "+"specified hours: " + hours + ". number of hours must be in the [0..23] range.";
messagedialog.showerror(controller.getmainframe(), msg);
return false;
}
if (minutes < 0 || minutes > 59) {
string msg = owner+" : "+"specified minutes: " + minutes + ". number of minutes must be in the [0..59] range.";
messagedialog.showerror(controller.getmainframe(), msg);
return false;
}
if (seconds < 0 || seconds > 59) {
string msg = owner+" : "+"specified seconds: " + seconds + ". number of seconds must be in the [0..59] range.";
messagedialog.showerror(controller.getmainframe(), msg);
return false;
}
return true;
}
正则方法为:
public static boolean timecheck(string time, string owner) {
//检查时间字符串time是否满足格式“hh:mm:ss”,若不满足显示相应消息,并返回false
string regex = "(([01]\\d)|(2[0-3])):[0-5]\\d(:[0-5]\\d)?";
if(!time.matches(regex)){
string msg = owner+" : "+"time is invalid.";
messagedialog.showerror(controller.getmainframe(), msg);
return false;
}
return true;
}
  真是很好很强大啊!!不过上述正则“((2[0-3])|([01]\d)):[0-5]\d(:[0-5]\d)?”实现居然不能匹配“3:3:3”,郁闷!
  将正则改为“((2[0-3])|([0-1]?\d)):[0-5]?\d(:[0-5]?\d)?”倒是可以匹配“3:3:3”这种了,但“3:65:34”显然是不对的,却又匹配出两个来,晕!
  将正则改为“((2[0-3])|([0-1]?\d)):[0-5]?\d(:[0-5]?\d)”倒是可以匹配“3:3:3”,也能正确判断“3:65:34”,却又没法判断“3:34”这种格式了。唉~~~~

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