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显示随机的5个数

2017年12月12日  | 移动技术网IT编程  | 我要评论
复制代码 代码如下:

@echo off
:: 求1-100范围内随机的不同5个数值
:: 生成0-99之间的随机数列 r1
::
::
::
@echo off
setlocal enabledelayedexpansion
:: 初始化顺序数列
for /l %%i in (0,1,99) do (
set rnum%%i=%%i
)
:: 对数列进行随机交换
for /l %%i in (0,1,99) do (
set /a rnd=!random! %% 100
call set tmp=%%rnum!rnd!%%
set rnum!rnd!=!rnum%%i!
set rnum%%i=!tmp!
)
set rnum
pause
goto :eof

@echo off
:: code by jm 2006-1-5 cmd@xp
:begin
cls
set times=0
set count=0
:loop
set /a num=%random%%%99+1
if not defined num%num% (
set num%num%=%num%
set /a count+=1
call echo %%num%%
)
set /a times+=1
if %times% equ 20 (
for /l %%i in (1,1,99) do set num%%i=
set times=0
)
if %count% lss 5 goto loop
pause>nul
goto begin
@echo off
:: code by jm 2007-1-6 cmd@xp
:: 因为用到了 echo|find 的结构，速度比较慢
::
:begin
cls
set count=0
:loop
set /a num=%random%%%100+1
echo %str%|find " %num% ">nul&&goto loop
call set str=%%str%% %num%
set /a count+=1
if %count% lss 5 goto loop
echo %str%
set str=
pause
goto begin

@echo off&setlocal enabledelayedexpansion
::
::
for /l %%a in (1;1;5) do (
set/a b=!random!%%99+1
call :pp !b!
)
goto :eof
:pp
if not defined %1 (set %1=a) else goto loop
echo %1
goto :eof
:loop
set/a b=!random!%%99+1
call :pp !b!

@echo off
::
::
set max=100
set n=5
:start
cls
echo %time%
set num=
set tmp$=
:loop
set /a randomloop=(%random%+%random%+%random%)/3%%%max%+1
for %%n in (%tmp$%) do if "%randomloop%" == "%%n" goto loop
call set tmp$=%%tmp$%% %randomloop%
set /a num+=1
set random_%num%=%randomloop%
if %num% lss %n% goto loop
echo %tmp$%
echo %time%
pause
goto start
exit

@echo off
::
::
:start
cls
set num=
set tmp$=
:loop
set /a randomloop=%random%%%99+1
for %%n in (%tmp$%) do if "%randomloop%" == "%%n" goto loop
call set tmp$=%%tmp$%% %randomloop%
set /a num+=1
set random_%num%=%randomloop%
if %num% lss 5 goto loop
for /l %%n in (1,1,%num%) do call set /p= %%random_%%n%%<nul
echo.
pause
goto start
exit

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