表结构:
数据:
需求:
按照company_id不同分组,然后分别求出相同company_id相邻记录touch_time的差值
sql:
select r1.company_id, r1.touch_time, r2.touch_time, r1.touch_time - r2.touch_time from (select (@rownum := @rownum + 1) as rownum, info.company_id, info.touch_time from sys_touch_info info, (select @rownum := 0) r where info.touch_time is not null order by info.company_id) r1 left join (select (@index := @index + 1) as rownum, info.company_id, info.touch_time from sys_touch_info info, (select @index := 0) r where info.touch_time is not null order by info.company_id) r2 on r1.company_id = r2.company_id and r1.rownum = r2.rownum - 1
结果:
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