我要评论需求：知道开始时间结束时间，求这段时间内输入星期一或星期二…的日期们
思路：用毫秒数来判断
/* 获取时间段内属于星期一(*)的日期们
* begin: 开始时间
* end：结束时间
* weekNum：星期几 {number}
*/
function getWeek (begin, end, weekNum){
var dateArr = new Array();
var stimeArr = begin.split("-");//=>["2018", "01", "01"]
var etimeArr = end.split("-");//=>["2018", "01", "30"]
var stoday = new Date();
stoday.setUTCFullYear(stimeArr[0], stimeArr[1]-1, stimeArr[2]);
var etoday = new Date();
etoday.setUTCFullYear(etimeArr[0], etimeArr[1]-1, etimeArr[2]);
var unixDb = stoday.getTime();//开始时间的毫秒数
var unixDe = etoday.getTime();//结束时间的毫秒数
for (var k = unixDb; k <= unixDe;) {
let needJudgeDate = msToDate(parseInt(k)).withoutTime;
//不加这个if判断直接push的话就是已知时间段内的所有日期
if (new Date(needJudgeDate).getDay() === weekNum) {
dateArr.push(needJudgeDate);
}
k = k + 24*60*60*1000;
}
return dateArr;
}
//根据毫秒数获取日期
function msToDate (msec) {
let datetime = new Date(msec);
let year = datetime.getFullYear();
let month = datetime.getMonth();
let date = datetime.getDate();
let hour = datetime.getHours();
let minute = datetime.getMinutes();
let second = datetime.getSeconds();
let result1 = year +
'-' +
((month + 1) >= 10 ? (month + 1) : '0' + (month + 1)) +
'-' +
((date + 1) < 10 ? '0' + date : date) +
' ' +
((hour + 1) < 10 ? '0' + hour : hour) +
':' +
((minute + 1) < 10 ? '0' + minute : minute) +
':' +
((second + 1) < 10 ? '0' + second : second);
let result2 = year +
'-' +
((month + 1) >= 10 ? (month + 1) : '0' + (month + 1)) +
'-' +
((date + 1) < 11 ? '0' + date : date);
let result = {
hasTime: result1,
withoutTime: result2
};
return result;
}
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