1 //传入一个map<string,long> 返回它按value排序后的结果 sort为正序还是倒序(-1倒序),size为要几条数据 2 private static map<string, long> sortmapbyvalues(map<string, long> amap, int sort, int size) { 3 4 set<map.entry<string, long>> mapentries = amap.entryset(); 5 6 list<map.entry<string, long>> alist = new linkedlist<map.entry<string, long>>(mapentries); 7 8 collections.sort(alist, new comparator<map.entry<string, long>>() { 9 10 @override 11 public int compare(map.entry<string, long> ele1, 12 map.entry<string, long> ele2) { 13 if (sort < 0) { 14 return ele2.getvalue().compareto(ele1.getvalue()); 15 } 16 return ele1.getvalue().compareto(ele2.getvalue()); 17 } 18 }); 19 // storing the list into linked hashmap to preserve the order of insertion. 20 map<string, long> amap2 = new linkedhashmap<string, long>(); 21 for (map.entry<string, long> entry : alist) { 22 amap2.put(entry.getkey(), entry.getvalue()); 23 if (amap2.size() == size) { 24 break; 25 } 26 } 27 return amap2; 28 }
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