我要评论复制代码 代码如下:
import java.io.ioexception;
import java.io.inputstream;
import java.net.url;
import javax.servlet.servletconfig;
import javax.servlet.servletexception;
import javax.servlet.servletoutputstream;
import javax.servlet.http.httpservlet;
import javax.servlet.http.httpservletrequest;
import javax.servlet.http.httpservletresponse;
/**
* take any request and proxy it to the given redirect_base.
* for example, if this servlet lives at
*
* http://foo.com/forward
*
* and is inititialized with the redirect_base
*
* http://bar.com/some/path
*
* then a get request like
*
* http://foo.com/forward?quux=mumbley
*
* will return the results of a get from
*
* http://bar.com/some/path?quux=mumbley
*
* this is not robust and generalized; it's simple and quick.
*
* @author jdf
*
*/
public class proxyservlet extends httpservlet
{
private final static string copyright = com.ibm.dogear.copyright.short;
public static final string redirect_base = "com.ibm.bl.servlet.redirectservlet.redirect_base";
private string redirectbase;
@override
public void init(servletconfig config) throws servletexception
{
super.init(config);
redirectbase = getrequiredparam(redirect_base);
}
@override
protected void doget(httpservletrequest req, httpservletresponse resp) throws ioexception
{
string querystring = req.getquerystring();
url url = new url(redirectbase + (querystring != null ? "?" + querystring : ""));
copyinputstreamtooutputstream(url.openstream(), resp.getoutputstream());
}
private void copyinputstreamtooutputstream(inputstream in, servletoutputstream out)
throws ioexception
{
try
{
try
{
byte[] buffer = new byte[1024];
int n;
while ((n = in.read(buffer)) != -1)
out.write(buffer, 0, n);
}
finally
{
out.close();
}
}
finally
{
in.close();
}
}
protected string getrequiredparam(string param) throws servletexception
{
string result = getservletconfig().getinitparameter(param);
if (result == null) {
throw new servletexception(getclass() + " requires " + param + " param");
}
return result;
}
}
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