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178. Rank Scores solution

2018年03月03日  | 移动技术网IT编程  | 我要评论

格雅手表6152g,豪门新娘的无心情人,掠爱

problem:

Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking. Note that after a tie, the next ranking number should be the next consecutive integer value. In other words, there should be no "holes" between ranks.

+----+-------+
| Id | Score |
+----+-------+
| 1  | 3.50  |
| 2  | 3.65  |
| 3  | 4.00  |
| 4  | 3.85  |
| 5  | 4.00  |
| 6  | 3.65  |
+----+-------+

For example, given the above Scores table, your query should generate the following report (order by highest score):

+-------+------+
| Score | Rank |
+-------+------+
| 4.00  | 1    |
| 4.00  | 1    |
| 3.85  | 2    |
| 3.65  | 3    |
| 3.65  | 3    |
| 3.50  | 4    |
+-------+------+
 
My statement:
 

Select Scores.Score, count(ranking.Score) as Rank 
from Scores,
(select distinct score from Scores) as ranking
where Scores.Score<=ranking.Score
group by Scores.Id
order by Scores.score Desc;

 

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