采莲曲歌词,小卓玛上学,形考答案
微软提供的控件//www.jb51.net/codes/9709.html
前台
<%@ page language="c#" autoeventwireup="true" codefile="default.aspx.cs" inherits="_default" %>
<!doctype html public "-//w3c//dtd xhtml 1.0 transitional//en" "http://www.w3.org/tr/xhtml1/dtd/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head runat="server">
<title>html文件上传标签</title>
</head>
<body>
<form id="form1" runat="server">
<div>
<input id="file1" type="file" runat="server" />
<asp:button id="btn_up" runat="server" text="上传" onclick="btn_up_click" />
</div>
</form>
</body>
</html>
后台
protected void btn_up_click(object sender, eventargs e)
{
string spath = server.mappath("~/test/");
string filename = file1.postedfile.filename;
int idx = filename.lastindexof(@"\");
string shortname = filename.substring(idx + 1);//获得文件名
this.file1.postedfile.saveas(spath + shortname);
}
end
官方给出的使用方法：
需要在要目录下新建两个目录:upfile和upimg
添加一个fileupload控件.一个button.一个image.一个label
关键代码:
string name = fileupload1.filename;//获得上传文件的名字.
string size = fileupload1.postedfile.contentlength.tostring();//文件大小.
string type = fileupload1.postedfile.contenttype;//文件类型.
string type2 = name.substring(name.lastindexof(".") + 1);//lastindexof()最后一个索引位置匹配.substring()里面的+1是重载.
string ipath = server.mappath("upimg") + "\\" + name;//取得根目录下面的upimg目录的路径.
string fpath = server.mappath("upfile") + "\\" + name;
string wpath = "upimg\\" + name;//获得虚拟路径.
if (type2 == "jpg" || type2 == "gif" || type2 == "bmp" || type2 == "png")
{
fileupload1.saveas(ipath);//保存方法,参数是一个地址字符串.
image1.imageurl = wpath;
label1.text = "你传的文件名是:" + name + "<br>文件大小为:" + size + "字节<br>文件类型是:" + type +
"<br>后缀是:" + type2 + "<br>实际路径是:" + ipath + "<br>虚拟路径是:" + fpath;
image1.visible = true;
}
else
{
image1.visible = false;
fileupload1.saveas(fpath);
label1.text = "你传的文件名是:" + name + "<br>文件大小为:" + size + "字节<br>文件类型是:" + type +
"<br>后缀是:" + type2 + "<br>实际路径是:" + ipath + "<br>虚拟路径是:" + fpath;
}
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