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SQLserver中cube：多维数据集实例详解

2017年11月02日  | 移动技术网IT编程  | 我要评论

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1、cube:生成多维数据集，包含各维度可能组合的交叉表格，使用with 关键字连接 with cube

根据需要使用union all 拼接

判断 某一列的null值来自源数据还是 cube 使用grouping关键字

grouping([档案号]) = 1 ： null值来自cube（代表所有的档案号）
grouping([档案号]) = 0 ： null值来自源数据

举例：

select * into ##get
from 
  (select *
    from ( select
      case
      when (grouping([档案号]) = 1) then
      '合计'
      else [档案号]
      end as '档案号',
      case
      when (grouping([系列]) = 1) then
      '合计'
      else [系列]
      end as '系列',
      case
      when (grouping([店长]) = 1) then
      '合计'
      else [店长]
      end as '店长', sum (剩余次数) as '总剩余',
      case
      when (grouping([店名]) = 1) then
      '合计'
      else [店名]
      end as '店名'
    from ##pudiancard
    group by [档案号], [店名], [店长], [系列]
    with cube
    having grouping([店名]) != 1
        and grouping([档案号]) = 1 --and grouping([系列]) = 1 ) as m
    union
    all 
      (select *
        from ( select
          case
          when (grouping([档案号]) = 1) then
          '合计'
          else [档案号]
          end as '档案号',
          case
          when (grouping([系列]) = 1) then
          '合计'
          else [系列]
          end as '系列',
          case
          when (grouping([店长]) = 1) then
          '合计'
          else [店长]
          end as '店长', sum (剩余次数) as '总剩余',
          case
          when (grouping([店名]) = 1) then
          '合计'
          else [店名]
          end as '店名'
        from ##pudiancard
        group by [档案号], [店名], [店长], [系列]
        with cube
        having grouping([店名]) != 1
            and grouping([店长]) != 1 ) as p )
        union
        all 
          (select *
            from ( select
              case
              when (grouping([档案号]) = 1) then
              '合计'
              else [档案号]
              end as '档案号',
              case
              when (grouping([系列]) = 1) then
              '合计'
              else [系列]
              end as '系列',
              case
              when (grouping([店长]) = 1) then
              '合计'
              else [店长]
              end as '店长', sum (剩余次数) as '总剩余',
              case
              when (grouping([店名]) = 1) then
              '合计'
              else [店名]
              end as '店名'
            from ##pudiancard
            group by [档案号], [店名], [店长], [系列]
            with cube
            having grouping([店名]) != 1
                and grouping([店长]) != 1 ) as w )
            union
            all 
              (select *
                from ( select
                  case
                  when (grouping([档案号]) = 1) then
                  '合计'
                  else [档案号]
                  end as '档案号',
                  case
                  when (grouping([系列]) = 1) then
                  '合计'
                  else [系列]
                  end as '系列',
                  case
                  when (grouping([店长]) = 1) then
                  '合计'
                  else [店长]
                  end as '店长', sum (剩余次数) as '总剩余',
                  case
                  when (grouping([店名]) = 1) then
                  '合计'
                  else [店名]
                  end as '店名'
                from ##pudiancard
                group by [档案号], [店名], [店长], [系列]
                with cube
                having grouping([店名]) = 1
                    and grouping([店长]) = 1
                    and grouping([档案号]) = 1 ) as k ) ) as t

2、rollup:功能跟cube相似

3、将某一列的数据作为列名，动态加载，使用存储过程，拼接字符串

declare @st nvarchar (max) = '';select @st =@st + 'max(case when [系列]=''' + cast ([系列] as varchar) + ''' then [总剩余] else null end ) as [' + cast ([系列] as varchar) + '],'
from ##get
group by [系列]; print @st;

4、根据某一列分组，分别建表

select
				'select row_number() over(order by [卡项] desc) as [序号], [会员],[档案号],[卡项],[剩余次数],[员工],[店名] into ' + ltrim([店名]) + ' from 查询 where [店名]=''' + [店名] + ''' order by [卡项] desc'
		from
			查询
		group by
			[店名]

总结

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