2016全国高考答案,永城信息港,yinqi
自己做了一个tcp工具，在学习动画的时候踩了坑，需求是根据上线变绿色，离线变灰色，如果连接断开了，则变为灰色
问题现象：
可以看到点击“连接”，“离线”的时候动画是正常的，但是当tcp超时断开后，虽然离线按钮变为连接了，却没有执行离线动画
关键源代码如下
我要评论
class bsjtcpthread(qtcore.qthread):
recv_signal = qtcore.pyqtsignal(str)
send_signal = qtcore.pyqtsignal(str)
def __init__(self, socketcp, onbtn, heartcheck, senbtn, scene):
super().__init__()
self.s = socketcp
self.yqtool = bianlifunction()
self.onbtn = onbtn
self.heartcheck = heartcheck
self.sendbtn = senbtn
self.scene1 = scene
def run(self):
"""线程"""
global stopsingle
stopsingle = 0
while 1:
btcpreceive = self.s.recv(1024)
tcpreceive1 = str(binascii.b2a_hex(btcpreceive), encoding="utf-8")
tcpreceive = ""
i = 0
while i < len(tcpreceive1) - 1: # 十六进制数据处理,两个字节隔开
if i == len(tcpreceive1) - 2:
tcpreceive += tcpreceive1[i:i + 2]
i += 2
else:
tcpreceive += tcpreceive1[i:i + 2] + " "
i += 2
if tcpreceive == "":
stopsingle = 1
self.s.shutdown(2)
self.s.close()
self.onbtn.settext("连接")
self.scene1.offlinecol.start() # 启动离线动画
self.heartcheck.setchecked(false)
self.heartcheck.setvisible(false)
self.sendbtn.setdisabled(true)
else:
self.recv_signal.emit(tcpreceive)
if stopsingle == 1:
break
然后再启动线程
self.tcpth = bsjtcpthread(self.s, self.onbtn, self.heartcheck, self.sendbtn, self.scene)
self.tcpth.recv_signal.connect(self.fillrecvmsg)
self.tcpth.send_signal.connect(self.fillsendmsg)
self.tcpth.start()
问题点：
经过谷爹搜索，终于找到了问题原因详见https://stackoverflow.com/questions/44328750/pyqt-qgraphicscene-move-item-in-background-thread
大致原因就是qgraphics scene 不是一个安全的线程对象，我们不能直接在线程中去改变主程序的状态，我们必须通过信号的方式去更新qgraphics
解决方法：
首先，我们编辑一个信号方法
def threadanimate(self, message):
if message == "1":
self.scene.offlinecol.start()
然后添加相关信号槽
self.tcpth = bsjtcpthread(self.s, self.onbtn, self.heartcheck, self.sendbtn)
self.tcpth.recv_signal.connect(self.fillrecvmsg)
self.tcpth.send_signal.connect(self.fillsendmsg)
self.tcpth.animate_signal.connect(self.threadanimate) # 添加一个动画信号
self.tcpth.start()
在线程中发出离线动画的信号
class bsjtcpthread(qtcore.qthread):
recv_signal = qtcore.pyqtsignal(str)
send_signal = qtcore.pyqtsignal(str)
animate_signal = qtcore.pyqtsignal(str)
def __init__(self, socketcp, onbtn, heartcheck, senbtn):
super().__init__()
self.s = socketcp
self.yqtool = bianlifunction()
self.onbtn = onbtn
self.heartcheck = heartcheck
self.sendbtn = senbtn
def run(self):
"""线程"""
global stopsingle
stopsingle = 0
while 1:
btcpreceive = self.s.recv(1024)
tcpreceive1 = str(binascii.b2a_hex(btcpreceive), encoding="utf-8")
tcpreceive = ""
i = 0
while i < len(tcpreceive1) - 1: # 十六进制数据处理,两个字节隔开
if i == len(tcpreceive1) - 2:
tcpreceive += tcpreceive1[i:i + 2]
i += 2
else:
tcpreceive += tcpreceive1[i:i + 2] + " "
i += 2
if tcpreceive == "":
stopsingle = 1
self.s.shutdown(2)
self.s.close()
self.onbtn.settext("连接")
self.animate_signal.emit("1")
self.heartcheck.setchecked(false)
self.heartcheck.setvisible(false)
self.sendbtn.setdisabled(true)
else:
self.recv_signal.emit(tcpreceive)
if stopsingle == 1:
break
然后就可以了，这个和qthread多线程收发消息原理一样
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