当前位置: 移动技术网 > IT编程>开发语言>c# > C#字符串自增自减算法详解

C#字符串自增自减算法详解

2019年07月18日  | 移动技术网IT编程  | 我要评论

c#实现字符串自增和自减运算,供大家参考,具体内容如下

1.数字从 0-9 变化;

2.字母从 a-z、a-z 变化;

3.其它字符跳过;

4.以上变化依据其ascii码值;

/// <summary>
 /// 字符串运算
 /// </summary>
 public class stringoperation
 {


  /// <summary>
  /// 通过ascii码值,对字符串自增1
  /// </summary>
  /// <param name="pstr">输入字符串</param>
  /// <returns></returns>
  public static string stringincreaseone(string pstr)
  {
   var vretstr = pstr;
   if (0 == pstr.length)
   {
    vretstr = "1";
   }
   else
   {
    // 将最后一个字符与之前的字符串分开
    string votherstr = pstr.substring(0, pstr.length - 1);
    int vintchar = (int)pstr[pstr.length - 1]; //转ascii码值
    if (48 <= vintchar && vintchar <= 57) //是数字(0 - 9)
    {
     vintchar++; //自增1
     if (vintchar == 58) // 进一位
     {
      vintchar = 48;
      votherstr = stringincreaseone(votherstr);
     }
    }
    else if (65 <= vintchar && vintchar <= 90) //是字母(a - z)
    {
     vintchar++; //自增1
     if (vintchar == 91) 
     {
      vintchar = 65;
      votherstr = stringincreaseone(votherstr);
     }
    }
    else if (97 <= vintchar && vintchar <= 122) //是字母(a - z)
    {
     vintchar++; //自增1
     if (vintchar == 123)
     {
      vintchar = 97;
      votherstr = stringincreaseone(votherstr); 
     }
    }
    else // 其它字符 -> 跳过
    {
     votherstr = stringincreaseone(votherstr);
    }
    vretstr = votherstr + (char)vintchar;
   }
   return vretstr;
  }

  /// <summary>
  /// 通过ascii码值,对字符串自减1
  /// </summary>
  /// <param name="pstr">输入字符串</param>
  /// <returns></returns>
  public static string stringreducingone(string pstr)
  {
   var vretstr = pstr;
   if (0 == pstr.length)
   {
    vretstr = "9";
   }
   else
   {
    string votherstr = pstr.substring(0, pstr.length - 1);
    int vintchar = (int)pstr[pstr.length - 1]; //转ascii码值
    if (48 <= vintchar && vintchar <= 57) //是数字(0 - 9)
    {
     vintchar--;
     if (vintchar == 47)
     {
      vintchar = 57;
      votherstr = stringreducingone(votherstr);
     }
    }
    else if (65 <= vintchar && vintchar <= 90) //是数字(a - z)
    {
     vintchar--; 
     if (vintchar == 64)
     {
      vintchar = 90;
      votherstr = stringreducingone(votherstr);
     }
    }
    else if (97 <= vintchar && vintchar <= 122) //是数字(a - z)
    {
     vintchar--;
     if (vintchar == 96)
     {
      vintchar = 122;
      votherstr = stringreducingone(votherstr);
     }
    }
    else // 其它字符 -> 跳过
    {
     votherstr = stringreducingone(votherstr);
    }
    vretstr = votherstr + (char)vintchar;
   }
   return vretstr;
  }

  /// <summary>
  /// 通过ascii码值,对字符串自增
  /// </summary>
  /// <param name="pstr">输入字符串</param>
  /// <param name="pcount">自增个数</param>
  /// <returns></returns>
  public static string stringincrease(string pstr, int pcount)
  {
   string vretstr = pstr;
   for (int i = 0; i < pcount; i++)
   {
    vretstr = stringincreaseone(vretstr);
   }
   return vretstr;
  }

  /// <summary>
  /// 通过ascii码值,对字符串自减
  /// </summary>
  /// <param name="pstr">输入字符串</param>
  /// <param name="pcount">自减个数</param>
  /// <returns></returns>
  public static string stringreducing(string pstr, int pcount)
  {
   string vretstr = pstr;
   for (int i = 0; i < pcount; i++)
   {
    vretstr = stringreducingone(vretstr);
   }   
   return vretstr;
  }
  


 }

以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持移动技术网。

如对本文有疑问, 点击进行留言回复!!

相关文章:

验证码:
移动技术网