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C#实现洗牌算法

2019年07月18日  | 移动技术网IT编程  | 我要评论

c#洗牌算法,简单演示!

算法一、

/// <summary>
/// 洗牌算法
/// </summary>
private void test()
{
 int[] icards = new int[54];
 for (int i = 0; i < icards.length; i++)
 {
 icards[i] = i + 1;
 }
 //
 random rand = new random();
 int itarget = 0, icardtemp = 0;
 for (int i = 0; i < icards.length; i++)
 {
 itarget = rand.next(0, icards.length);
 icardtemp = icards[i];
 icards[i] = icards[itarget];
 icards[itarget] = icardtemp;
 }
 
 for (int i = 0; i < icards.length; i++)
 {
 response.write("第" + (i + 1) + "张牌是:" + icards[i] + "<br/>");
 }
}

算法二、

public void shuffle()
  {
   
   int[] cards = new int[54] { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53 };
   //创建一个临时的扑克牌组
   int[] newcards = new card[54];
   //bool变量数组
   bool[] assigned = new bool[54];

   random sourcegen = new random();
   for (int i = 0; i < 54; i++)
   {
    int destcard = 0;     //随机数保存空间
    bool foundcard = false;
    while (foundcard == false)
    {
     //生成一个0到54之间的随机数
     destcard = sourcegen.next(54);
     if (assigned[destcard] == false)
     {
      foundcard = true;
     }
    }
    assigned[destcard] = true;
    newcards[destcard] = cards[i];
   }

算法三、

public void reshuffle()
  {
   int[] cards = new int[54] { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53 };
   random ram = new random();
   int currentindex;
   int tempvalue;
   for (int i = 0; i < 54; i++)
   {
    currentindex = ram.next(0, 54 - i);
    tempvalue = cards[currentindex];
    cards[currentindex] = cards[53 - i];
    cards[53 - i] = tempvalue;
   }
  }

15

相比一下,第三个更简单,更高效!

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