C# 读写XML文件实例代码_c#

c#史上最简单读写xml文件方式，创建控制台应用程序赋值代码，就可以运行，需要改动，请自行调整

using system;
using system.collections.generic;
using system.io;
using system.linq;
using system.text;
using system.threading.tasks;
using system.xml;

namespace consoleapp1
{
  class program
  {
    public const string xmlpath = "info.xml";

    static void main(string[] args)
    {

      idictionary<string, list<string>> infos = new dictionary<string, list<string>>();

      infos.add("evan", new list<string>() { "123", "456" });

      savexml(infos);

      readxml();
      console.readkey();
    }

    public static void savexml(idictionary<string, list<string>> infos)
    {
      if (infos == null || infos.count == 0)
      {
        return;
      }

      xmldocument xmldoc = new xmldocument();

      xmldeclaration dec = xmldoc.createxmldeclaration("1.0", "utf-8", null);

      xmldoc.appendchild(dec);

      xmlelement _infos = xmldoc.createelement("infos");

      foreach (keyvaluepair<string, list<string>> item in infos)
      {
        xmlelement info = xmldoc.createelement("info");

        xmlelement name = xmldoc.createelement("file1");
        name.innertext = item.key;

        info.appendchild(name);

        xmlnode filelist = xmldoc.createelement("filelist");

        info.appendchild(filelist);

        foreach (string number in item.value)
        {
          xmlelement filed = xmldoc.createelement("filed");
          filed.innertext = number;

          filelist.appendchild(filed);
        }

        _infos.appendchild(info);
      }

      xmldoc.appendchild(_infos);

      xmldoc.save(xmlpath);
    }

    public static idictionary<string, list<string>> readxml()
    {
      idictionary<string, list<string>> infos = new dictionary<string, list<string>>();

      if (file.exists(xmlpath))
      {
        xmldocument xmldoc = new xmldocument();

        xmldoc.load(xmlpath);

        xmlnode xn = xmldoc.selectsinglenode("infos");

        xmlnodelist xnl = xn.childnodes;

        foreach (xmlnode xnf in xnl)
        {
          xmlelement xe = (xmlelement)xnf;

          xmlnode namenode = xe.selectsinglenode("file1");

          string name = namenode.innertext;
          console.writeline(name);
          xmlnode filelist = xe.selectsinglenode("filelist");

          list<string> list = new list<string>();

          foreach (xmlnode item in filelist.childnodes)
          {
            list.add(item.innertext);
          }

          infos.add(name, list);
        }
      }

      return infos;
    }
  }
}

内容扩展：

实例代码

dim domxmldocument as system.xml.xmldocument 
  dim tmppath as string = apptempfilepath 
  dim xmlfile as string = tmppath + "＼testxml.xml" 
 '窗体加载事件 
  private sub testxml_load(byval sender as system.object, byval e as system.eventargs) handles mybase.load 
  '读xml过程测试通过 
  dim domxmldocument as system.xml.xmldocument 
  dim tmppath as string = apptempfilepath 
  dim xmlfile as string = tmppath + "＼testxml.xml" 
  dim reader as system.xml.xmlreader = nothing 
  try 
  reader = new xml.xmltextreader(xmlfile) 
  'reader. 
  while reader.read 
  me.lboxxml.items.add(reader.name + reader.value) 
  end while 
  catch ex as exception 
  msgbox(ex.message) 
  finally 
  if not (reader is nothing) then 
  reader.close() 
  end if 
  end try 
  end sub 
  '载入xml事件 
  private sub btnxmlload_click(byval sender as system.object, byval e as system.eventargs) handles btnxmlload.click 
  'me.lboxxml.items.clear() 
  ''读xml过程测试通过 
  'dim reader as system.xml.xmlreader = nothing 
  'try 
  ' reader = new xml.xmltextreader(xmlfile) 
  ' while reader.read 
  ' me.lboxxml.items.add(reader.name + ":" + reader.value) 
  ' end while 
  'catch ex as exception 
  ' msgbox(ex.message) 
  'finally 
  ' if not (reader is nothing) then 
  ' reader.close() 
  ' end if 
  'end try 
  dim ds as new dataset 
  try 
  '如果直接使用ds做datasource则不会展开datagrid，用dv则能直接显示正确。 
  ds.readxml(xmlfile) 
  dim tb as datatable 
  dim dv as dataview 
  tb = ds.tables(0) 
  dv = new dataview(tb) 
  datagrid1.datasource = dv 
  'datagrid1.datamember = "testxmlmember" 
  'datagrid1.datamember = "employeefname" 
  'dim dxd as new xmldatadocument 
  catch ex as exception 
  msgbox(ex.message.tostring) 
  end try 
  end sub 
  '保存新建xml内容事件 
  private sub btnsavenew_click(byval sender as system.object, byval e as system.eventargs) handles btnsavenew.click 
  dim mytw as new xmltextwriter(tmppath + "＼testxmlwrite.xml", nothing) 
  mytw.writestartdocument() 
  mytw.formatting = formatting.indented 
  mytw.writestartelement("team") 
  mytw.writestartelement("player") 
  mytw.writeattributestring("name", "george zip") 
  mytw.writeattributestring("position", "qb") 
  mytw.writeelementstring("nickname", "zippy") 
  mytw.writeelementstring("jerseynumber", xmlconvert.tostring(7)) 
  mytw.writeendelement() 
  mytw.writeendelement() 
  mytw.writeenddocument() 
  mytw.close() 
  end sub

文件很大的情况下，可以考虑手动实现数据更新适配器，比如手动实现一个xml节点搜索/更新，这样就不用重写整个xml。
如果程序的i/o不是主要问题，还是用实体类整个的写入更新吧，毕竟数据的完整性是第一位的。
如是文章类的，对该目录建一个xml索引文件来存放文章的编号，url等，用xml的attribute作为标记不同字段，内容页面可以用另外的html或xml页面存放，用linq to xml操作数据，效率不是很差，个人观点。当搜索时候只要查询指定文件名xml或文件类型就可以了。

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