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因为短日期不足2位，所以在网页排版的时候，影响美观，下面两个函数可以解决这个问题。
2020-2-7短日期 变 2020-02-07长日期
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function fstime(times)
dim years,months,days
if len(times)=0 then exit function
years=year(times)
months=right("0"&month(times),2)
days=right("0"&day(times),2)
times=years&"-"&months&"-"&days
fstime=times
end function
2020-2-7 23:37:5短日期 变 2020-02-07 23:37:05长日期
function fltime(times)
dim years,months,days,hours,minutes,seconds
if len(times)=0 then exit function
years=year(times):months=right("0"&month(times),2)
days=right("0"&day(times),2):hours=right("0"&hour(times),2)
minutes=right("0"&minute(times),2):seconds=right("0"&second(times),2)
fltime=years&"-"&months&"-"&days&" "&hours&":"&minutes&":"&seconds
end function
pw_sys 日期格式转换函数
<%
rem pw_sys 日期格式转换函数
function datetimeformat(datetime,format)
select case format
case "1"
datetimeformat=""&year(datetime)&"年"&month(datetime)&"月"&right("0" & day(datetime),2)&"日"
case "2"
datetimeformat=""&month(datetime)&"月"&right("0" & day(datetime),2)&"日"
case "3"
datetimeformat=""&year(datetime)&"-"&month(datetime)&"-"&right("0" & day(datetime),2)&""
case "4"
datetimeformat=""&year(datetime)&"/"&month(datetime)&"/"&right("0" & day(datetime),2)&""
case "5"
datetimeformat=""&month(datetime)&"/"&right("0" & day(datetime),2)&""
case "6"
datetimeformat=""&year(datetime)&"年"&month(datetime)&"月"&right("0" & day(datetime),2)&"日<font color=red> "&formatdatetime(datetime,4)&"</font>"
case "7"
temp="星期日,星期一,星期二,星期三,星期四,星期五,星期六"
temp=split(temp,",")
datetimeformat=temp(weekright("0" & day(datetime),2)-1)
case "8"
datetimeformat=""&month(datetime)&"-"&right("0" & day(datetime),2)&""
case "9"
if len(hour(datetime)) = 1 then
str="0"&hour(datetime)
else
str=hour(datetime)
end if
datetimeformat=datetimeformat(datetime,1)&" "&str&":"&minute(datetime)
case "10"
datetimeformat=""&year(datetime)&"年"&month(datetime)&"月"
case else
datetimeformat=datetime
end select
end function
%>
程序代码（把yyyy-mm-dd格式的日期中的月份和日期转换成两位数字的方法）
dim today
today=date '避免重复调用date，所以赋值给一个变量
today=year(today) & "-" & right("0" & month(today),2) & "-" & right("0" & day(today),2)
asp中一段自动补位的函数
function formatsn(getnum,getbit) dim formatsnnum,formatsnpre,formatsnj formatsnnum = getbit – len(getnum) for formatsnj = 1 to formatsnnum formatsnpre = formatsnpre & "0" next formatsn = formatsnpre & getnum end function
使用方法
formatsn(getnum,getbit)
getnum 计数
getbit 共几位
以上就是asp中格式化时间短日期补0变两位长日期的方法的详细内容，更多关于asp短日期补0的资料请关注移动技术网其它相关文章！
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asp中Request.ServerVariables的参数集合
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