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C#实现农历日历的方法

2019年07月18日  | 移动技术网IT编程  | 我要评论

本文实例讲述了c#实现农历日历的方法。分享给大家供大家参考。

具体实现方法如下:

复制代码 代码如下:
//天干 
private  static string []tiangan =   {"甲","乙","丙","丁","戊","己","庚","辛","壬","癸"};    
//地支 
private  static string []dizhi =     {"子","丑","寅","卯","辰","巳","午","未","申","酉","戌","亥"};    
//十二生肖 
private  static string []shengxiao = {"鼠","牛","虎","兔","龙","蛇","马","羊","猴","鸡","狗","猪"};    
//农历日期 
private  static string []dayname =   {"*","初一","初二","初三","初四","初五","初六","初七","初八","初九","初十",  "十一","十二","十三","十四","十五",             "十六","十七","十八","十九","二十",             "廿一","廿二","廿三","廿四","廿五",                   "廿六","廿七","廿八","廿九","三十"};    
//农历月份
private static string []monthname =  {"*","正","二","三","四","五","六","七","八","九","十","十一","腊"};    
//公历月计数天 
private  static int []monthadd =      {0,31,59,90,120,151,181,212,243,273,304,334}; 
//农历数据 
private static int []lunardata =    {2635,333387,1701,1748,267701,694,2391,133423,1175,396438            ,3402,3749,331177,1453,694,201326,2350,465197,3221,3402            ,400202,2901,1386,267611,605,2349,137515,2709,464533,1738            ,2901,330421,1242,2651,199255,1323,529706,3733,1706,398762            ,2741,1206,267438,2647,1318,204070,3477,461653,1386,2413            ,330077,1197,2637,268877,3365,531109,2900,2922,398042,2395            ,1179,267415,2635,661067,1701,1748,398772,2742,2391,330031            ,1175,1611,200010,3749,527717,1452,2742,332397,2350,3222            ,268949,3402,3493,133973,1386,464219,605,2349,334123,2709            ,2890,267946,2773,592565,1210,2651,395863,1323,2707,265877}; 
/// <summary> 
/// 获取对应日期的农历
///
/// </summary> 
/// <param name="dtday">公历日期</param>
///
///<returns></returns> 
public string getlunarcalendar(datetime dtday)
{
    string syear = dtday.year.tostring(); string smonth = dtday.month.tostring();
    string sday = dtday.day.tostring();
    int year;
    int month;
    int day;
    try {
    year = int.parse(syear);
    month = int.parse(smonth);
    day = int.parse(sday);
    }
    catch {
    year = datetime.now.year;
    month = datetime.now.month;
    day = datetime.now.day;
    }
    int nthedate;
    int nisend;
    int k, m, n, nbit, i;
    string calendar = string.empty;
    //计算到初始时间1921年2月8日的天数:1921-2-8(正月初一)  
    nthedate = (year - 1921) * 365 + (year - 1921) / 4 + day + monthadd[month - 1] - 38;
    if ((year % 4 == 0) && (month > 2)) nthedate += 1;
    //计算天干,地支,月,日
    nisend = 0; m = 0; k = 0; n = 0;
    while (nisend != 1)
    {
 if (lunardata[m] < 4095) k = 11; else k = 12; n = k; while (n >= 0)
 {     //获取lunardata[m]的第n个二进制位的值
     nbit = lunardata[m];
     for (i = 1; i < n + 1; i++) nbit = nbit / 2;
     nbit = nbit % 2;
     if (nthedate <= (29 + nbit)) { nisend = 1; break; }
     nthedate = nthedate - 29 - nbit; n = n - 1;
 }
 if (nisend == 1) break; m = m + 1;
    }
    year = 1921 + m; month = k - n + 1; day = nthedate;

    #region 格式化日期显示为三月廿四
    if (k == 12)
    {
 if (month == lunardata[m] / 65536 + 1)
     month = 1 - month;
 else if (month > lunardata[m] / 65536 + 1)
     month = month - 1;
    }
    //生肖//
    calendar = shengxiao[(year - 4) % 60 % 12].tostring() + "年 ";
    //   //            //天干//   //
    calendar += tiangan[(year - 4) % 60 % 10].tostring();
    //   //            //地支//   //
    calendar += dizhi[(year - 4) % 60 % 12].tostring() + " ";
    ////   //农历月//
    if (month < 1)
 //
 calendar += "闰" + monthname[-1 * month].tostring() + "月";
    else
 calendar += monthname[month].tostring() + "月";
    ////   //农历日// 
    calendar += dayname[day].tostring() + "日";//// 
    return calendar;////  
    #endregion
}

希望本文所述对大家的c#程序设计有所帮助。

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