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C# -- 模拟扑克牌发牌

2019年11月05日  | 移动技术网IT编程  | 我要评论

c# -- 模拟扑克牌发牌

1.  user 类： 玩家

public class user
{
    private list<papercard> listcard = new list<papercard>();

    public string name { get; set; }

    public user(string strname)
    {
        this.name = strname;
    }
    public void add(papercard p)
    {
        listcard.add(p);
    }

    public void reset()
    {
        listcard.clear();
    }

    public void introduce()
    {
        string strcards = "";

        for (int i = 0; i < listcard.count; i++)
        {
            if (i == 0)
            {
                strcards += listcard[i].name;
            }
            else
            {
                strcards += ", " + listcard[i].name;
            }
        }
        console.writeline("\r\n--------------------------------------------");
        console.write("我是{0}，", name);
        console.write("我手中的扑克牌有{0}张:\r\n{1}\r\n", listcard.count,strcards);
    }
}

 

2. papercard类：纸牌

public class papercard
{
    public string type { get; set; }
    public string number { get; set; }
    public papercard(string strtype, string strnumber)
    {
        this.type = strtype;
        this.number = strnumber;
    }

    public string name
    {
        get
        {
            return string.format("{0}{1}", this.type, this.number);
        }

        private set { }
    }
}

 

3. 模拟发牌过程

public void testplay()
{
    //产生扑克牌
    console.writeline("正在生成扑克牌...");
    list<papercard> mycards = new list<papercard>();
    string[] strtype = { "红桃", "黑桃", "梅花", "方块" };
    string[] strnumber = { "a", "2", "3", "4", "5", "6", "7", "8", "9", "10", "j", "q", "k" };
    papercard[] othercard = { new papercard("大王", ""), new papercard("小王", "") };

    for (int i = 0; i < strnumber.length; i++)
    {
        for (int j = 0; j < strtype.length; j++)
        {
            papercard p = new papercard(strtype[j], strnumber[i]);
            mycards.add(p);
        }
    }

    for (int j = 0; j < othercard.length; j++)
    {
        mycards.add(othercard[j]);
    }

    //洗牌
    console.writeline("正在洗牌...");
    stack<papercard> stackcard = new stack<papercard>();
    random r = new random();

    while (mycards.count>0)
    {
        int iindex = r.next(0, mycards.count);
        stackcard.push(mycards[iindex]);
        mycards.removeat(iindex);
    }



    //发牌
    console.writeline("开始发牌...");
    list<user> listuser = new list<user>() {
        new user("大师兄"),
        new user("二师兄"),
        new user("三师弟")
    };

    while (stackcard.count > 0)
    {
        for (int s = 0; s < listuser.count; s++)
        {
            listuser[s].add(stackcard.pop());
        }
    }
    console.writeline("发牌完成！");


    //看牌
    foreach (var item in listuser)
    {
        item.introduce();
    }
}

 

测试：

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